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Coat Color Genetics(by Tina Porter Lakeway Kennel)
Have you ever wondered what
color you next litter of puppies will be? Or why your two sable dogs
produced a litter of black and tans? It all has to do with
genetics- specifically coat color genetics.
Just to make sure we are all starting out in the same spot, here is
a quick refresher on basic Mendelian genetics. If you already have
a good grasp of genetics you might want to skip this part J Trait: a feature
or characteristic that is inherited. It is usually represented by a
letter. Example- coat length = L Gene: the
specific segment of DNA on a chromosome that codes for a particular
trait. Example- gene for coat length is located on
chromosome. 12. Allele: version
of the trait/gene. Each allele is given a version of the letter
assigned to a trait. Example- the gene for coat length has two
alleles- one for the smooth coat (L), and one for plush coat (l).
Chromosomes:
“packets” of genes. Dogs have 78 chromosomes, 38 pairs and two sex
chromosomes (determine gender). The paired chromosomes (sometimes
called autosomes or homologous) contain the same Think of it in
terms of a shoe store. They have 38 different pairs of shoes
(chromosomes). They are all different styles (different chromosome
pairs carry different genes), but each pair have the same style
(homologous chromosomes have the same genes). This means you have 2
copies of a gene – one on the right shoe, and one on the left. As
you look closely at your pair of shoes you’ll notice they are not
exactly the same – one is a righty, the other a lefty. (you have 2
copies of the gene, but maybe not the same alleles). One of the
shoe/chromosomes you inherited from the sire, the other from the
dam.
Genotype- what alleles you have for a particular gene. Remember you have 2 alleles, one from mom, one from dad. A genotype is written as 2 letters, each letter represents an allele. Heterozygous:
has 2 different alleles in the genotype. Ex- Ll Homozygous: has
the same alleles in the genotype Ex- LL or ll Phenotype: what
the dog looks like. Ex- a dog with the genotype ll has the phenotype
of a plush coat. Dominant: an
allele that is expressed in the phenotype no matter what other
allele you have. Dominant alleles are written as capital letters.
Back to our coat length example- if a dog has the genotype LL or Ll
they have a short coat. L is dominant to l, short hair is dominant
to long hair. Recessive: An
allele that is only expressed if a dominant allele is NOT present.
Recessive alleles are written as lower case letters. The only
genotype a long haired dog can have is ll. (* Yes, I know there are
“smush” coats out there. There is another gene that modifies coat
length aside from “L”). We all know that you get ½ of
your chromosomes from the sire, and half from the dam. But how can
you tell which ones the pups will get? Simple- you can’t. But you
can make predictions using a Punnett Square. Let’s use this sample problem
to give you an idea. You breed a heterozygous short haired bitch
(let’s say her father was a plush coat so you know she has at least
one recessive allele from him) to a plush coated dog. You want to
know many plush coated puppies you will get.
Alleles L= smooth coat, l=
plush coat
Sire’s genotype- by looking back we remember that he can
only be plush coated if he has both recessive alleles, so he must be
ll.
Dam’s genotype- as discussed
earlier she is heterozygous Sire gives his offspring either
allele
Dam gives either the L or l allele The genotypes in the boxes are
the possible genotypes of the puppies for this trait… Ll and ll. The Ll’s are smooth
coated, and 2/4 have this genotype, the other ½ are plush coated
like their dad. Does that mean ½ your litter will be smooth, the
other ½ plush? No. These genotypes are the possibilities for ONE
puppy. Each puppy has a 50% chance of being smooth coated. It is
like flipping a coin. you have a 50% chance of it turning up heads,
but it is possible to flip heads 10 times in a row. So the puppies
could all be smooth coats, or all plush. You may be thinking this is
too easy to be true- and you’d be right! Coat color is much more
complicated than the simple Punnett square example above. It is a
polygenic trait, which means more than one gene is responsible for
coding for the trait of coat color. Not only are there many genes
that code for coat color , but there are many unknown genes that
modify the genes that code for coat color? Scientists are still
trying to work out the exact inheritance patterns and very few of
them agree with each other., I have tried to include as many
different theories as possible.
Note- series here refers which series of alleles that the particular
gene has, so the Agouti series is the list of alleles for the agouti
gene. All alleles are listed in order of dominance, from most to
least. Remember- your dog has 2
alleles from each one of these series (not to mention a bunch
of other ones) controlling their coat color! Agouti Series : this
gene controls the distribution of black hair on the body
Let me give you an example of
how this works…in theory Bear (black, with some tan on his legs) and
Tessa (dark brown sable) when bred together produced bi-colored
pups, dark brown sable pups, and solid black pups. Solid black is a
recessive, so these pups must have the genotype aa…
meaning each pup got one of those “a”’s from each parent.. so
Bear’s genotype is a ? and Tessa’s is a ?.
Since Tessa is sable, we know she has the aw allele, so
her genotype is awa. Bear is a little trickier…by
looking at his phenotype we know he’s not sable, or black and tan,
so he doesn’t carry those alleles. If he was aa the all the
puppies he produced with Tessa would be either sable or solid black
(try doing the Punnett square!), but that doesn’t explain the
bi-colored puppies. It is my personal guess he is ata,
and that these two alleles work together (there may be some other
modifying genes acting on this as well) to form the darker
bi-color. Does this mean all bi-colored dogs carry the black
recessive? It is possible- and it is a pet theory of mine. If you
have a bi-colored dog, or breed one, I’d love to hear from you! From this Tessa/Bear breeding
the bi-colored dogs like Simon do carry the black recessive given to
them by Tessa. (If they hadn’t gotten her black recessive allele
they would have gotten her sable allele- which is dominant, so
they’d be sable!) There is also an unidentified
modification that makes a otherwise solid looking dog have a
different colored undercoat. They are not truly sable (the guard
hair are all one color) and don’t carry the sable gene. This appears
to be recessive. B Series – controls the
ability of black pigment to form.
C Series- This gene
effects the intensity of pigment produced. Some believe this is the
gene responsible for producing solid white.
D Series- Controls the
intensity of black pigment.
http://bluedogpics.8m.com/cherokee.htm This site has some
great pictures showing dilute dogs. There can be dilute livers too!
E Series- Extension series
Dogs with the ee
genotype have the black pigment in their coat fade out by the time
they are 2 years old. It doesn’t affect the pigment of the nose or
pads. Many people confuse this with a golden sable, the difference
is a golden sable dog will have a black tip at the end of its tail
an ee dog has a red tip to it’s tail. Int Series- Controls the
intensity of tan markings
The genes above are the major
players in determining coat color in our breed. There are other
ones out there, such as a gene that causes the salt and peppering
down the backs of black and tan dogs (thought to be caused by a
recessive allele). There is another series for spotting. For more information on coat
color genetics: Carver,EA, 1984. Coat Color
Genetics of the German Shepherd Dog. J.Hered. 75:247-252 Willis, M.B. 1989.Genetics of
the Dog. H.F.&G Witherby, London Willis, M.B. 1991. The German
Shepherd Dog: A Genetic History, H.F.&G Witherby, London Color Genertics by John Ayotte, Jan 1998
http://www.mindspring.com/~ayottej/frankenhaus/colorgen.htm German Shepherd Dogs website http://www.cluebus.com/holly/gsdfaq.html#Color |
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